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Moment of inertia of a circle radius 0.5
Moment of inertia of a circle radius 0.5






Since angular momentum is conserved, the initial angular momentum of the system is equal to the angular momentum of the bullet embedded in the disk immediately after impact. Thus, the net angular momentum of the system is mvR. The initial angular momentum of the cylinder is zero. The initial angular momentum of the bullet is mvR, which is taken about the rotational axis of the disk the moment before the collision. Thus, the angular momentum along this axis is conserved.

moment of inertia of a circle radius 0.5

The connecting rod length between centres is 1.2 m and the cylinder bore is 0.5 m. When the crank has travelled 30° from T.D.C., the difference between the driving and the back pressures is 0.45 N/mm2. The mass of the reciprocating parts is 250 kg. \[\frac\): A bullet is fired horizontally and becomes embedded in the edge of a disk that is free to rotate about its vertical axis.įor the system of the bullet and the cylinder, no external torque acts along the vertical axis through the center of the disk. The crank-pin circle radius of a horizontal engine is 300 mm.

moment of inertia of a circle radius 0.5 moment of inertia of a circle radius 0.5

The angular momentum of a system of particles around a point in a fixed inertial reference frame is conserved if there is no net external torque around that point:








Moment of inertia of a circle radius 0.5